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Popular >

vertices 4x^2+y^2=4

Solution

vertices

4 x^{2} + y^{2} = 4

Solution

(0, 2), (0, - 2)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

4 x^{2} + y^{2} = 4 :

Ellipse with center

(h, k) = (0, 0), b = 2, a = 1

(0, 0 + 2), (0, 0 - 2)

Refine

(0, 2), (0, - 2)

Popular Examples

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36 x^{2} + 9 y^{2} + 48 x - 36 y + 43 = 0

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16 x^{2} - 96 x + 4 y^{2} = - 80

vertices x^2+16y^2-64=0 vertices

x^{2} + 16 y^{2} - 64 = 0

vertices ((x-7)^2)/4+((y+3)^2)/(16)=1 vertices

\frac{( x - 7 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

vertices ((x+3)^2)/9+((y-1)^2)/(25)=1 vertices

\frac{( x + 3 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{25} = 1

Frequently Asked Questions (FAQ)

What is the vertices 4x^2+y^2=4 ?
The vertices 4x^2+y^2=4 is (0,2),(0,-2)