What is the vertices ((x-1)^2)/3+((y-2)^2)/5 =1 ?

The vertices ((x-1)^2)/3+((y-2)^2)/5 =1 is (1,2+sqrt(5)),(1,2-sqrt(5))

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vertices ((x-1)^2)/3+((y-2)^2)/5 =1

vertices

\frac{( x - 1 ) ^{2}}{3} + \frac{( y - 2 ) ^{2}}{5} = 1

(1, 2 + 5), (1, 2 - 5)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{( x - 1 ) ^{2}}{3} + \frac{( y - 2 ) ^{2}}{5} = 1 :

Ellipse with center

(h, k) = (1, 2), b = 5, a = 3

(1, 2 + 5), (1, 2 - 5)

\frac{( x - 3 ) ^{2}}{64} + \frac{( y + 5 ) ^{2}}{81} = 1

x^{2} + 4 y^{2} + 6 x + 16 y + 21 = 0

x^{2} + \frac{( y + 2 ) ^{2}}{4} = 1

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1

4 x^{2} + 25 y^{2} - 100 = 0

What is the vertices ((x-1)^2)/3+((y-2)^2)/5 =1 ?
The vertices ((x-1)^2)/3+((y-2)^2)/5 =1 is (1,2+sqrt(5)),(1,2-sqrt(5))