What is the vertices ((x-1)^2)/2+(y^2)/1 =1 ?

The vertices ((x-1)^2)/2+(y^2)/1 =1 is (1+sqrt(2),0),(1-sqrt(2),0)

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vertices ((x-1)^2)/2+(y^2)/1 =1

vertices

\frac{( x - 1 ) ^{2}}{2} + \frac{y ^{2}}{1} = 1

(1 + 2, 0), (1 - 2, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

\frac{( x - 1 ) ^{2}}{2} + \frac{y ^{2}}{1} = 1 :

Ellipse with center

(h, k) = (1, 0), a = 2, b = 1

(1 + 2, 0), (1 - 2, 0)

\frac{( x - 1 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{16} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{49} = 1

4 x^{2} + 9 y^{2} - 32 x - 36 y + 64 = 0

x^{2} + 16 y^{2} = 1

2 x^{2} + 7 y^{2} = 14

What is the vertices ((x-1)^2)/2+(y^2)/1 =1 ?
The vertices ((x-1)^2)/2+(y^2)/1 =1 is (1+sqrt(2),0),(1-sqrt(2),0)