What is the vertices (x^2)/(94)+(y^2)/(36)=1 ?

The vertices (x^2)/(94)+(y^2)/(36)=1 is (sqrt(94),0),(-sqrt(94),0)

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vertices (x^2)/(94)+(y^2)/(36)=1

vertices

\frac{x ^{2}}{94} + \frac{y ^{2}}{36} = 1

(94, 0), (- 94, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

\frac{x ^{2}}{94} + \frac{y ^{2}}{36} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 94, b = 6

(0 + 94, 0), (0 - 94, 0)

Refine

(94, 0), (- 94, 0)

x^{2} + 2 y^{2} - 2 x + 8 y + 5 = 0

\frac{x ^{2}}{49} + \frac{y ^{2}}{36} = 1

\frac{x ^{2}}{81} + \frac{y ^{2}}{64} = 1

\frac{( x - 3 ) ^{2}}{25} + \frac{( y + 1 ) ^{2}}{16} = 1

\frac{x ^{2}}{100} + \frac{y ^{2}}{36} = 1

What is the vertices (x^2)/(94)+(y^2)/(36)=1 ?
The vertices (x^2)/(94)+(y^2)/(36)=1 is (sqrt(94),0),(-sqrt(94),0)