What is (16x^2)/(144)+(9y^2)/(144)=1 ?

The solution to (16x^2)/(144)+(9y^2)/(144)=1 is Ellipse with (h,k)=(0,0),a=3,b=4

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(16x^2)/(144)+(9y^2)/(144)=1

\frac{16 x ^{2}}{144} + \frac{9 y ^{2}}{144} = 1

(h, k) = (0, 0), a = 3, b = 4

Solution steps

\frac{16 x ^{2}}{144} + \frac{9 y ^{2}}{144} = 1

Rewrite

\frac{16 x ^{2}}{144} + \frac{9 y ^{2}}{144} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 3

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2 x^{2} - 200 x + y^{2} + 4 y + 379 = 0

\frac{x ^{2}}{\frac{25}{4}} + \frac{y ^{2}}{4} = 1

9 x^{2} + 4 y^{2} - 90 x + 189 = 0

x^{2} + 30 x + 12 y^{2} = 0

What is (16x^2)/(144)+(9y^2)/(144)=1 ?
The solution to (16x^2)/(144)+(9y^2)/(144)=1 is Ellipse with (h,k)=(0,0),a=3,b=4