What is ((x-1)^2}{25}+\frac{(y-1)^2)/3 =1 ?

The solution to ((x-1)^2}{25}+\frac{(y-1)^2)/3 =1 is Ellipse with (h,k)=(1,1),a=5,b=sqrt(3)

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((x-1)^2}{25}+\frac{(y-1)^2)/3 =1

\frac{( x - 1 ) ^{2}}{25} + \frac{( y - 1 ) ^{2}}{3} = 1

(h, k) = (1, 1), a = 5, b = 3

Solution steps

\frac{( x - 1 ) ^{2}}{25} + \frac{( y - 1 ) ^{2}}{3} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{25} + \frac{( y - 1 ) ^{2}}{3} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{5 ^{2}} + \frac{( y - 1 ) ^{2}}{( 3 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 1), a = 5, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 1), a = 5, b = 3

x^{2} - 4 y + y^{2} = 0

\frac{( x - 0 ) ^{2}}{25} + \frac{( y - 0 ) ^{2}}{2.25} = 1

\frac{( x - 5 ) ^{2}}{49} + \frac{( y - 8 ) ^{2}}{11} = 1

\frac{( x + 4 ) ^{2}}{4} + \frac{( y - 1 ) ^{2}}{9} = 1

4 x^{2} + 2 x + y^{2} - 10 y = 6

What is ((x-1)^2}{25}+\frac{(y-1)^2)/3 =1 ?
The solution to ((x-1)^2}{25}+\frac{(y-1)^2)/3 =1 is Ellipse with (h,k)=(1,1),a=5,b=sqrt(3)