x^2+8y^2=8

Solution

x^{2} + 8 y^{2} = 8

(h, k) = (0, 0), a = 22, b = 1

Solution steps

x^{2} + 8 y^{2} = 8

Rewrite

x^{2} + 8 y^{2} = 8

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 22, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 22, b = 1

9 x^{2} + 4 y^{2} + 36 x - 8 y + 4 = 0

7 x^{2} + 2 y^{2} = 14

4 x^{2} + 25 y^{2} - 6 x + 200 y + 304 = 0

(\frac{x + 4}{3})^{2} + (\frac{y + 4}{9})^{2} = (\frac{457}{81})^{2}

\frac{( x - 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{36} = 1

What is x^2+8y^2=8 ?
The solution to x^2+8y^2=8 is Ellipse with (h,k)=(0,0),a=2sqrt(2),b=1