What is (y/8)^2+(x/7)^2=1 ?

The solution to (y/8)^2+(x/7)^2=1 is Ellipse with (h,k)=(0,0),a=7,b=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(y/8)^2+(x/7)^2=1

(\frac{y}{8})^{2} + (\frac{x}{7})^{2} = 1

(h, k) = (0, 0), a = 7, b = 8

Solution steps

(\frac{y}{8})^{2} + (\frac{x}{7})^{2} = 1

Rewrite

(\frac{y}{8})^{2} + (\frac{x}{7})^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 8

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 8, a = 7

\frac{x ^{2}}{64} + \frac{y ^{2}}{9} = 1

\frac{( x - 4 ) ^{2}}{36} + \frac{( y - 2 ) ^{2}}{6} - 1 = 0

8 x^{(2)} + 2 y^{(2)} + 16 x = 0

2 x^{2} + 5 y^{2} + 3 x + 30 y - 16 = 0

8 x^{2} + y^{2} = 10

What is (y/8)^2+(x/7)^2=1 ?
The solution to (y/8)^2+(x/7)^2=1 is Ellipse with (h,k)=(0,0),a=7,b=8