What is (x^2}{13}+\frac{y^2)/9 =1 ?

The solution to (x^2}{13}+\frac{y^2)/9 =1 is Ellipse with (h,k)=(0,0),a=sqrt(13),b=3

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(x^2}{13}+\frac{y^2)/9 =1

\frac{x ^{2}}{13} + \frac{y ^{2}}{9} = 1

(h, k) = (0, 0), a = 13, b = 3

Solution steps

\frac{x ^{2}}{13} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{13} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 13 ) ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 13, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 13, b = 3

\frac{( x + 3 ) ^{2}}{4} + \frac{( y - 4 ) ^{2}}{18} = 1

\frac{x}{x ^{2} + y ^{2}} = - \frac{3}{4}

\frac{( x + 1 ) ^{2}}{\frac{27}{4}} + \frac{( y - 4 ) ^{2}}{9} = 1

9 - x^{2} - 9 y^{2} = 0

\frac{( x - 5 ) ^{2}}{25} + \frac{( y - 3 ) ^{2}}{9} = 1

What is (x^2}{13}+\frac{y^2)/9 =1 ?
The solution to (x^2}{13}+\frac{y^2)/9 =1 is Ellipse with (h,k)=(0,0),a=sqrt(13),b=3