What is (x^2)/(169)+(y^2)/(36)=1 ?

The solution to (x^2)/(169)+(y^2)/(36)=1 is Ellipse with (h,k)=(0,0),a=13,b=6

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(x^2)/(169)+(y^2)/(36)=1

\frac{x ^{2}}{169} + \frac{y ^{2}}{36} = 1

(h, k) = (0, 0), a = 13, b = 6

Solution steps

\frac{x ^{2}}{169} + \frac{y ^{2}}{36} = 1

Rewrite

\frac{x ^{2}}{169} + \frac{y ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 3 ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 13, b = 6

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 13, b = 6

3 y^{2} + x^{2} - 12 y + 9 = 0

\frac{( x - 1 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{2} = 1

16 x^{2} + 4 y^{2} + 16 x + 49 y - 81 = 0

\frac{( x - 4 ) ^{2}}{10} + \frac{( y - 2 ) ^{2}}{6} = 1

9 x^{2} - 18 x + 4 y^{2} - 27 = 0

What is (x^2)/(169)+(y^2)/(36)=1 ?
The solution to (x^2)/(169)+(y^2)/(36)=1 is Ellipse with (h,k)=(0,0),a=13,b=6