What is ((x-7)^2)/(25)+((y+9)^2)/(36)=1 ?

The solution to ((x-7)^2)/(25)+((y+9)^2)/(36)=1 is Ellipse with (h,k)=(7,-9),a=5,b=6

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((x-7)^2)/(25)+((y+9)^2)/(36)=1

\frac{( x - 7 ) ^{2}}{25} + \frac{( y + 9 ) ^{2}}{36} = 1

(h, k) = (7, - 9), a = 5, b = 6

Solution steps

\frac{( x - 7 ) ^{2}}{25} + \frac{( y + 9 ) ^{2}}{36} = 1

Rewrite

\frac{( x - 7 ) ^{2}}{25} + \frac{( y + 9 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 7 ) ^{2}}{5 ^{2}} + \frac{( y - ( - 9 ) ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (7, - 9), a = 5, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (7, - 9), b = 6, a = 5

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13 x^{2} + 23 y^{2} - 51 x - 19 y - 4 = 0

250 = 2 x^{2} + \frac{y ^{2}}{2}

6 x^{2} + 18 y^{2} + 24 x = 0

What is ((x-7)^2)/(25)+((y+9)^2)/(36)=1 ?
The solution to ((x-7)^2)/(25)+((y+9)^2)/(36)=1 is Ellipse with (h,k)=(7,-9),a=5,b=6