What is 9(x+4)^2+13(y-1)^2=117 ?

The solution to 9(x+4)^2+13(y-1)^2=117 is Ellipse with (h,k)=(-4,1),a=sqrt(13),b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9(x+4)^2+13(y-1)^2=117

9 (x + 4)^{2} + 13 (y - 1)^{2} = 117

(h, k) = (- 4, 1), a = 13, b = 3

Solution steps

9 (x + 4)^{2} + 13 (y - 1)^{2} = 117

Rewrite

9 (x + 4)^{2} + 13 (y - 1)^{2} = 117

in the form of the standard ellipse equation

\frac{( x - ( - 4 ) ) ^{2}}{( 13 ) ^{2}} + \frac{( y - 1 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 4, 1), a = 13, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 4, 1), a = 13, b = 3

2 y^{2} + x^{2} - 2 x - 4 = 0

x^{2} + 2 x + 4 y^{2} - 12 y + 7 = 0

78 = 32 (x - \frac{3}{2})^{2} + 50 (y + 1)^{2}

x^{2} + 2 y^{2} - 3 x + 8 y - 1 = 0

7 x^{2} = 35 - 5 y^{2}

What is 9(x+4)^2+13(y-1)^2=117 ?
The solution to 9(x+4)^2+13(y-1)^2=117 is Ellipse with (h,k)=(-4,1),a=sqrt(13),b=3