What is ((x^2}{16})+(\frac{y^2)/9)=1 ?

The solution to ((x^2}{16})+(\frac{y^2)/9)=1 is Ellipse with (h,k)=(0,0),a=4,b=3

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((x^2}{16})+(\frac{y^2)/9)=1

(\frac{x ^{2}}{16}) + (\frac{y ^{2}}{9}) = 1

(h, k) = (0, 0), a = 4, b = 3

Solution steps

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 3

x^{2} + \frac{y ^{2}}{25} = 1

\frac{( x - 1 ) ^{2}}{25} + \frac{( y + 3 ) ^{2}}{100} = 1

\frac{x ^{2}}{1} + \frac{y ^{2}}{4} = 1

- \frac{x ^{2}}{4} - \frac{z ^{2}}{4} = 1

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} \leq 1

What is ((x^2}{16})+(\frac{y^2)/9)=1 ?
The solution to ((x^2}{16})+(\frac{y^2)/9)=1 is Ellipse with (h,k)=(0,0),a=4,b=3