What is (x^2}{140}+\frac{(y-6)^2)/4 =1 ?

The solution to (x^2}{140}+\frac{(y-6)^2)/4 =1 is Ellipse with (h,k)=(0,6),a=2sqrt(35),b=2

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(x^2}{140}+\frac{(y-6)^2)/4 =1

\frac{x ^{2}}{140} + \frac{( y - 6 ) ^{2}}{4} = 1

(h, k) = (0, 6), a = 235, b = 2

Solution steps

\frac{x ^{2}}{140} + \frac{( y - 6 ) ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{140} + \frac{( y - 6 ) ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 35 ) ^{2}} + \frac{( y - 6 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 6), a = 235, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 6), a = 235, b = 2

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9 x^{2} - 54 x + 4 y^{2} = - 45

x^{2} + 3 y^{2} + x - 2 y - 1 = 0

(\frac{x + 7}{16})^{2} + \frac{( y + 5 ) ^{2}}{16} = 1

3 x^{2} + 2 y^{2} + 12 x - 8 y - 16 = 0

What is (x^2}{140}+\frac{(y-6)^2)/4 =1 ?
The solution to (x^2}{140}+\frac{(y-6)^2)/4 =1 is Ellipse with (h,k)=(0,6),a=2sqrt(35),b=2