What is (x^2)/(100)+(y^2)/(50)=1 ?

The solution to (x^2)/(100)+(y^2)/(50)=1 is Ellipse with (h,k)=(0,0),a=10,b=5sqrt(2)

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(x^2)/(100)+(y^2)/(50)=1

\frac{x ^{2}}{100} + \frac{y ^{2}}{50} = 1

(h, k) = (0, 0), a = 10, b = 52

Solution steps

\frac{x ^{2}}{100} + \frac{y ^{2}}{50} = 1

Rewrite

\frac{x ^{2}}{100} + \frac{y ^{2}}{50} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 0 ^{2}} + \frac{( y - 0 ) ^{2}}{( 5 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 10, b = 52

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 10, b = 52

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 2

(2 x + 3)^{2} + (y - 2)^{2} = 26

4 x^{2} + y^{2} - 32 x + 4 y + 64 = 0

\frac{x ^{2}}{289} + \frac{y ^{2}}{225} = 1

2 x^{2} + 9 y^{2} - 18 = 0

What is (x^2)/(100)+(y^2)/(50)=1 ?
The solution to (x^2)/(100)+(y^2)/(50)=1 is Ellipse with (h,k)=(0,0),a=10,b=5sqrt(2)