What is ((x+7)^2)/6+((y+7)^2)/5 =1 ?

The solution to ((x+7)^2)/6+((y+7)^2)/5 =1 is Ellipse with (h,k)=(-7,-7),a=sqrt(6),b=sqrt(5)

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((x+7)^2)/6+((y+7)^2)/5 =1

\frac{( x + 7 ) ^{2}}{6} + \frac{( y + 7 ) ^{2}}{5} = 1

(h, k) = (- 7, - 7), a = 6, b = 5

Solution steps

\frac{( x + 7 ) ^{2}}{6} + \frac{( y + 7 ) ^{2}}{5} = 1

Rewrite

\frac{( x + 7 ) ^{2}}{6} + \frac{( y + 7 ) ^{2}}{5} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 7 ) ) ^{2}}{( 6 ) ^{2}} + \frac{( y - ( - 7 ) ) ^{2}}{( 5 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 7, - 7), a = 6, b = 5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 7, - 7), a = 6, b = 5

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What is ((x+7)^2)/6+((y+7)^2)/5 =1 ?
The solution to ((x+7)^2)/6+((y+7)^2)/5 =1 is Ellipse with (h,k)=(-7,-7),a=sqrt(6),b=sqrt(5)