What is ((x+1)^2)/(64)+((y-1)^2)/(100)=1 ?

The solution to ((x+1)^2)/(64)+((y-1)^2)/(100)=1 is Ellipse with (h,k)=(-1,1),a=8,b=10

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((x+1)^2)/(64)+((y-1)^2)/(100)=1

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{100} = 1

(h, k) = (- 1, 1), a = 8, b = 10

Solution steps

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{100} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{100} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{8 ^{2}} + \frac{( y - 1 ) ^{2}}{1 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 1), a = 8, b = 10

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, 1), b = 10, a = 8

1^{2} = (x - 0)^{2} + (y - 1)^{2}

\frac{x ^{2}}{24} + \frac{y ^{2}}{20} = 1

16 (x^{2}) + 9 (y^{2}) - 144 = 0

49 x^{2} + 16 y^{2} + 98 x - 64 y - 671 = 0

x^{2} - 6 x + 2 y^{2} + 4 y - 11 = 0

What is ((x+1)^2)/(64)+((y-1)^2)/(100)=1 ?
The solution to ((x+1)^2)/(64)+((y-1)^2)/(100)=1 is Ellipse with (h,k)=(-1,1),a=8,b=10