What is ((x+2)^2}{16}+\frac{(y+1)^2)/9 =1 ?

The solution to ((x+2)^2}{16}+\frac{(y+1)^2)/9 =1 is Ellipse with (h,k)=(-2,-1),a=4,b=3

Popular >

((x+2)^2}{16}+\frac{(y+1)^2)/9 =1

\frac{( x + 2 ) ^{2}}{16} + \frac{( y + 1 ) ^{2}}{9} = 1

(h, k) = (- 2, - 1), a = 4, b = 3

Solution steps

\frac{( x + 2 ) ^{2}}{16} + \frac{( y + 1 ) ^{2}}{9} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{16} + \frac{( y + 1 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{4 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, - 1), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 2, - 1), a = 4, b = 3

x^{2} + 4 y^{2} + 4 x + 32 y - 64 = 0

\frac{( x - 2 ) ^{2}}{10} + \frac{( y + 1 ) ^{2}}{25} = 1

36 x^{2} + 16 y^{2} + 144 x - 160 y - 32 = 0

9 x^{2} + 49 y^{2} - 114 x + 490 y + 1360 = 0

x^{2} + 4 z^{2} = 4

What is ((x+2)^2}{16}+\frac{(y+1)^2)/9 =1 ?
The solution to ((x+2)^2}{16}+\frac{(y+1)^2)/9 =1 is Ellipse with (h,k)=(-2,-1),a=4,b=3