What is 8x^2+3y^2=24 ?

The solution to 8x^2+3y^2=24 is Ellipse with (h,k)=(0,0),a=sqrt(3),b=2sqrt(2)

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8x^2+3y^2=24

8 x^{2} + 3 y^{2} = 24

(h, k) = (0, 0), a = 3, b = 22

Solution steps

8 x^{2} + 3 y^{2} = 24

Rewrite

8 x^{2} + 3 y^{2} = 24

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 3 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 22

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 22, a = 3

\frac{( x - 4 ) ^{2}}{9} + \frac{( y + 6 ) ^{2}}{4} = 1

9 x^{2} + 4 y^{2} + 18 x + 32 y + 37 = 0

\frac{x ^{2}}{100} + \frac{y ^{2}}{49} = 1

- x^{2} - 4 = y^{2}

x^{2} + 10 y^{2} - 6 x + 20 y + 18 = 0

What is 8x^2+3y^2=24 ?
The solution to 8x^2+3y^2=24 is Ellipse with (h,k)=(0,0),a=sqrt(3),b=2sqrt(2)