What is ((x+1)^2)/6+((y-1)^2)/3 =1 ?

The solution to ((x+1)^2)/6+((y-1)^2)/3 =1 is Ellipse with (h,k)=(-1,1),a=sqrt(6),b=sqrt(3)

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((x+1)^2)/6+((y-1)^2)/3 =1

\frac{( x + 1 ) ^{2}}{6} + \frac{( y - 1 ) ^{2}}{3} = 1

(h, k) = (- 1, 1), a = 6, b = 3

Solution steps

\frac{( x + 1 ) ^{2}}{6} + \frac{( y - 1 ) ^{2}}{3} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{6} + \frac{( y - 1 ) ^{2}}{3} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{( 6 ) ^{2}} + \frac{( y - 1 ) ^{2}}{( 3 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 1), a = 6, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 1, 1), a = 6, b = 3

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What is ((x+1)^2)/6+((y-1)^2)/3 =1 ?
The solution to ((x+1)^2)/6+((y-1)^2)/3 =1 is Ellipse with (h,k)=(-1,1),a=sqrt(6),b=sqrt(3)