What is (x+1)^2+(y^2)/4 =1 ?

The solution to (x+1)^2+(y^2)/4 =1 is Ellipse with (h,k)=(-1,0),a=1,b=2

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(x+1)^2+(y^2)/4 =1

(x + 1)^{2} + \frac{y ^{2}}{4} = 1

(h, k) = (- 1, 0), a = 1, b = 2

Solution steps

(x + 1)^{2} + \frac{y ^{2}}{4} = 1

Rewrite

(x + 1)^{2} + \frac{y ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 0), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, 0), b = 2, a = 1

9 x^{2} + y^{2} + 90 x - 4 y + 193 = 0

\frac{x ^{2}}{16} + \frac{x}{2} + \frac{y ^{2}}{4} + y + 1 = 0

9 x^{2} + 4 y^{2} - 27 x + 16 y - 119 = 0

x^{2} + 5 y^{2} + 2 x - 30 y + 36 = 0

\frac{x ^{2}}{64} + \frac{y ^{2}}{39} = 1

What is (x+1)^2+(y^2)/4 =1 ?
The solution to (x+1)^2+(y^2)/4 =1 is Ellipse with (h,k)=(-1,0),a=1,b=2