What is (x^2)/9+((y-4)^2)/7 =1 ?

The solution to (x^2)/9+((y-4)^2)/7 =1 is Ellipse with (h,k)=(0,4),a=3,b=sqrt(7)

Popular >

(x^2)/9+((y-4)^2)/7 =1

\frac{x ^{2}}{9} + \frac{( y - 4 ) ^{2}}{7} = 1

(h, k) = (0, 4), a = 3, b = 7

Solution steps

\frac{x ^{2}}{9} + \frac{( y - 4 ) ^{2}}{7} = 1

Rewrite

\frac{x ^{2}}{9} + \frac{( y - 4 ) ^{2}}{7} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 4 ) ^{2}}{( 7 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 4), a = 3, b = 7

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 4), a = 3, b = 7

(x + 4)^{2} + (\frac{y - 3}{4})^{2} = 1

\frac{( x - 1 ) ^{2}}{5} + \frac{( y - 3 ) ^{2}}{4} = 1

9 x^{2} + 4 y^{2} - 126 x - 40 y + 505 = 0

\frac{( x + 2 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{25} = 1

\frac{( x + 1 ) ^{2}}{1} + \frac{y ^{2}}{4} = 1

What is (x^2)/9+((y-4)^2)/7 =1 ?
The solution to (x^2)/9+((y-4)^2)/7 =1 is Ellipse with (h,k)=(0,4),a=3,b=sqrt(7)