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Popular >

area x^2+y^2<= 1

Solution

area

x^{2} + y^{2} \leq 1

Solution

A = π

Solution steps

A = π r^{2}

Find the radius

Radius given

x^{2} + y^{2} \leq 1 : r = 1

A = π 1^{2}

Refine

A = π

Popular Examples

area 2x^2+2y^2+6x-8y+12=0 area

2 x^{2} + 2 y^{2} + 6 x - 8 y + 12 = 0

area 2x^2-6x+2y^2+2y=45 area

2 x^{2} - 6 x + 2 y^{2} + 2 y = 45

area (x+4)^2+(y+6)^2=18 area

(x + 4)^{2} + (y + 6)^{2} = 18

area (x-3)^2+(y+4)^2=25 area

(x - 3)^{2} + (y + 4)^{2} = 25

area (x+1)^2+y^2=246 area

(x + 1)^{2} + y^{2} = 246

Frequently Asked Questions (FAQ)

What is the area x^2+y^2<= 1 ?
The area x^2+y^2<= 1 is A=pi