What is the circumference (x+2)^2+(y+5)^2=16 ?

The circumference (x+2)^2+(y+5)^2=16 is C=8pi

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circumference (x+2)^2+(y+5)^2=16

circumference

(x + 2)^{2} + (y + 5)^{2} = 16

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x + 2)^{2} + (y + 5)^{2} = 16 : r = 4

C = 2 π 4

Refine

C = 8 π

x^{2} + y^{2} - x - 6 y - 5 = 0

(x - 6)^{2} + (y + 5)^{2} = 64

x^{2} - 6 x + 2 y + y^{2} + 1 = 0

X^{2} + Y^{2} = 9

(x - 2)^{2} + (y + 3)^{2} = 11^{2}

What is the circumference (x+2)^2+(y+5)^2=16 ?
The circumference (x+2)^2+(y+5)^2=16 is C=8pi