What is the circumference (x-2)^2+(y-9)^2=16^2 ?

The circumference (x-2)^2+(y-9)^2=16^2 is C=32pi

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circumference (x-2)^2+(y-9)^2=16^2

circumference

(x - 2)^{2} + (y - 9)^{2} = 1 6^{2}

C = 32 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 2)^{2} + (y - 9)^{2} = 1 6^{2} : r = 16

C = 2 π 16

Refine

C = 32 π

x^{2} + y^{2} + 6 x - 4 y - 51 = 0

x^{2} + y^{2} - 4 x - 6 y + 9 = 0

x^{2} + y^{2} + 4 y - 4 = 0

x^{2} + y^{2} - 4 x - 12 = 0

4 x^{2} + 4 y^{2} + 28 x - 28 y - 24 = 0

What is the circumference (x-2)^2+(y-9)^2=16^2 ?
The circumference (x-2)^2+(y-9)^2=16^2 is C=32pi