What is the circumference x^2+y^2-8x-10y+40=0 ?

The circumference x^2+y^2-8x-10y+40=0 is C=2pi

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circumference x^2+y^2-8x-10y+40=0

circumference

x^{2} + y^{2} - 8 x - 10 y + 40 = 0

C = 2 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 8 x - 10 y + 40 = 0 : r = 1

C = 2 π 1

Refine

C = 2 π

x^{2} + 6 x + y^{2} - 8 y = 0

(x + 3)^{2} + (y + 2)^{2} = 9

(x - 3)^{2} + (y + 2)^{2} = 9

x^{2} + y^{2} - 2 x + 4 y = 0

x^{2} + y^{2} - 4 x + 10 y + 13 = 0

What is the circumference x^2+y^2-8x-10y+40=0 ?
The circumference x^2+y^2-8x-10y+40=0 is C=2pi