What is the circumference x^2+y^2-8x-6y-11=0 ?

The circumference x^2+y^2-8x-6y-11=0 is C=12pi

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circumference x^2+y^2-8x-6y-11=0

circumference

x^{2} + y^{2} - 8 x - 6 y - 11 = 0

C = 12 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 8 x - 6 y - 11 = 0 : r = 6

C = 2 π 6

Refine

C = 12 π

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

x^{2} + y^{2} = 7

x^{2} + y^{2} - 6 x + 8 y = 144

x^{2} + y^{2} = 4

(x - 2)^{2} + y^{2} = 16

What is the circumference x^2+y^2-8x-6y-11=0 ?
The circumference x^2+y^2-8x-6y-11=0 is C=12pi