What is the radius (x-2)^2+(y+3)^2=9 ?

The radius (x-2)^2+(y+3)^2=9 is r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius (x-2)^2+(y+3)^2=9

radius

(x - 2)^{2} + (y + 3)^{2} = 9

r = 3

Solution steps

(x - 2)^{2} + (y + 3)^{2} = 9

Rewrite

(x - 2)^{2} + (y + 3)^{2} = 9

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 3))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (2, - 3), r = 3

And the radius is:

r = 3

3 y^{2} + 3 x^{2} + 24 x + 32 = 0

(x + 4)^{2} + (y - 3)^{2} = 25

(x - 1)^{2} + (y - 4)^{2} = 25

(x + 2)^{2} + (y - 1)^{2} = 9

(x + 2)^{2} + (y - 3)^{2} = 16