What is the radius (y+4)^2+(x+3)^2=25 ?

The radius (y+4)^2+(x+3)^2=25 is r=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius (y+4)^2+(x+3)^2=25

radius

(y + 4)^{2} + (x + 3)^{2} = 25

r = 5

Solution steps

(y + 4)^{2} + (x + 3)^{2} = 25

Rewrite

(y + 4)^{2} + (x + 3)^{2} = 25

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 4))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 4), r = 5

And the radius is:

r = 5

(x - 1)^{2} + y^{2} = 9

(x - 10)^{2} + y^{2} = \frac{1}{4}

4 x^{2} + 4 y^{2} + 24 x - 32 y + 91 = 0

x^{2} + 16 x + y^{2} - 12 y = 0

(x - 2.5)^{2} + (y - 0.5)^{2} = 14.5