What is the radius x^2+y^2-4x+9x=16 ?

The radius x^2+y^2-4x+9x=16 is r=(sqrt(89))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius x^2+y^2-4x+9x=16

radius

x^{2} + y^{2} - 4 x + 9 x = 16

r = \frac{89}{2}

Solution steps

x^{2} + y^{2} - 4 x + 9 x = 16

Rewrite

x^{2} + y^{2} - 4 x + 9 x = 16

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - 0)^{2} = (\frac{89}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, 0), r = \frac{89}{2}

And the radius is:

r = \frac{89}{2}

(x + 2)^{2} + (y - 3)^{2} = (- 6)^{2}

x^{2} + y^{2} - 10 x + 4 y + 25 = 0

(x + 1)^{2} + (y + 3)^{2} = 4

x^{2} + y^{2} - 64 = 0

3 x^{2} + 5 x + 3 y^{2} + 6 y - 15 = 0

What is the radius x^2+y^2-4x+9x=16 ?
The radius x^2+y^2-4x+9x=16 is r=(sqrt(89))/2