What is the radius x^2+y^2-10x+16y+85=0 ?

The radius x^2+y^2-10x+16y+85=0 is r=2

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radius x^2+y^2-10x+16y+85=0

radius

x^{2} + y^{2} - 10 x + 16 y + 85 = 0

r = 2

Solution steps

x^{2} + y^{2} - 10 x + 16 y + 85 = 0

Rewrite

x^{2} + y^{2} - 10 x + 16 y + 85 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 8))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (5, - 8), r = 2

And the radius is:

r = 2

4 (x + 5)^{2} + 4 (y + 4)^{2} - 20 = 0

x^{2} + y^{2} + 2 x - 8 y - 19 = 0

x^{2} + y^{2} - 8 x - 13 y - 32 = 0

x^{2} + y^{2} - 6 x - 8 y + 9 = 0

(x - 9)^{2} + y^{2} - 32 = 0

What is the radius x^2+y^2-10x+16y+85=0 ?
The radius x^2+y^2-10x+16y+85=0 is r=2