What is the radius x^2+y^2-4x+12x=16 ?

The radius x^2+y^2-4x+12x=16 is r=4sqrt(2)

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radius x^2+y^2-4x+12x=16

radius

x^{2} + y^{2} - 4 x + 12 x = 16

r = 42

Solution steps

x^{2} + y^{2} - 4 x + 12 x = 16

Rewrite

x^{2} + y^{2} - 4 x + 12 x = 16

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 0)^{2} = (42)^{2}

Therefore the circle properties are:

(a, b) = (- 4, 0), r = 42

And the radius is:

r = 42

x^{2} + 8 x + y^{2} + 2 y + 8 = 0

x^{2} + y^{2} = 13

x^{2} + y^{2} = 11

x^{2} + y^{2} = 19

x^{2} + y^{2} + x + y = 0

What is the radius x^2+y^2-4x+12x=16 ?
The radius x^2+y^2-4x+12x=16 is r=4sqrt(2)