What is the radius 3(x+5)^2+3(y+2)^2=27 ?

The radius 3(x+5)^2+3(y+2)^2=27 is r=3

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radius 3(x+5)^2+3(y+2)^2=27

radius

3 (x + 5)^{2} + 3 (y + 2)^{2} = 27

r = 3

Solution steps

3 (x + 5)^{2} + 3 (y + 2)^{2} = 27

Rewrite

3 (x + 5)^{2} + 3 (y + 2)^{2} = 27

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 2))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 2), r = 3

And the radius is:

r = 3

x^{2} + y^{2} + 2 x + 10 y + 18 = 0

2 (x - 3)^{2} + 2 y^{2} = 8

3 x^{2} + 3 y^{2} - 12 x + 6 y - 12 = 0

x^{2} + y^{2} - 9 x + 4 y - 127 = 0

x^{2} + y^{2} + 14 x - 18 y + 49 = 0

What is the radius 3(x+5)^2+3(y+2)^2=27 ?
The radius 3(x+5)^2+3(y+2)^2=27 is r=3