Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

center (x+2)^2+(y-3)^2=15center center (x+5)^2+(y+2)^2=29center center x^2+y^2-16x+12y+64=0center center x^2+2x-4y+y^2=76center center x^2-2x+y^2-4y=0center

Frequently Asked Questions (FAQ)

  • What is the center x^2+y^2+4y-5=0 ?

    The center x^2+y^2+4y-5=0 is (0,-2)