What is the center [x+5]^2+[y+1]^2=9 ?

The center [x+5]^2+[y+1]^2=9 is (-5,-1)

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center [x+5]^2+[y+1]^2=9

center

[x + 5]^{2} + [y + 1]^{2} = 9

(- 5, - 1)

Solution steps

(x + 5)^{2} + (y + 1)^{2} = 9

Rewrite

(x + 5)^{2} + (y + 1)^{2} = 9

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 1))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 1), r = 3

And the center is:

(- 5, - 1)

x^{2} + (y - 1)^{2} = 49

3 x^{2} + 3 y^{2} - 18 x - 18 y + 42 = 0

(x - 4)^{2} + (y - 1)^{2} = 64

x^{2} + y^{2} - 6 x + 7 y - 16 = 0

(x - 5)^{2} + (y - 1)^{2} = 49