What is the center (x-5)^2+(y+2)^2=15 ?

The center (x-5)^2+(y+2)^2=15 is (5,-2)

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center (x-5)^2+(y+2)^2=15

center

(x - 5)^{2} + (y + 2)^{2} = 15

(5, - 2)

Solution steps

(x - 5)^{2} + (y + 2)^{2} = 15

Rewrite

(x - 5)^{2} + (y + 2)^{2} = 15

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 2))^{2} = (15)^{2}

Therefore the circle properties are:

(a, b) = (5, - 2), r = 15

And the center is:

(5, - 2)

x^{2} + (y + 5)^{2} = 100

(x + 5)^{2} + y^{2} = 64

\frac{x ^{2}}{49} + \frac{y ^{2}}{49} = 1

(x + 2)^{2} + (y - 2)^{2} = 20

4 x^{2} - 40 x + 4 y^{2} - 32 y = 5