What is the center (x+4)^2+(y+2)^2=25 ?

The center (x+4)^2+(y+2)^2=25 is (-4,-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

center (x+4)^2+(y+2)^2=25

center

(x + 4)^{2} + (y + 2)^{2} = 25

(- 4, - 2)

Solution steps

(x + 4)^{2} + (y + 2)^{2} = 25

Rewrite

(x + 4)^{2} + (y + 2)^{2} = 25

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 2))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 2), r = 5

And the center is:

(- 4, - 2)

(x - 12)^{2} + (y - 7)^{2} = 196

9 x^{2} + 36 x + 9 y^{2} + 72 y + 155 = 0

(x - 2)^{2} + (y - 5)^{2} = 49

\frac{( x + 7 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

x^{2} + 4 x + y^{2} + 6 y + 9 = 0

What is the center (x+4)^2+(y+2)^2=25 ?
The center (x+4)^2+(y+2)^2=25 is (-4,-2)