What is the center (x-2)^2+(y-1)^2=49 ?

The center (x-2)^2+(y-1)^2=49 is (2,1)

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center (x-2)^2+(y-1)^2=49

center

(x - 2)^{2} + (y - 1)^{2} = 49

(2, 1)

Solution steps

(x - 2)^{2} + (y - 1)^{2} = 49

Rewrite

(x - 2)^{2} + (y - 1)^{2} = 49

in the form of the standard circle equation

(x - 2)^{2} + (y - 1)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (2, 1), r = 7

And the center is:

(2, 1)

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(x - 5)^{2} + (y + 4)^{2} = 4