Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

center x^2+(y-5)^2=36center center x^2+y^2+12x-12y+36=0center center x^2+(y-5)^2=16center center (x+1)^2+y^2=25center center 4x^2+4y^2-8x-4y=11center

Frequently Asked Questions (FAQ)

  • What is the center x^2+y^2-4x-8y-5=0 ?

    The center x^2+y^2-4x-8y-5=0 is (2,4)