What is the center x^2+y^2+2x-6y-6=0 ?

The center x^2+y^2+2x-6y-6=0 is (-1,3)

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center x^2+y^2+2x-6y-6=0

center

x^{2} + y^{2} + 2 x - 6 y - 6 = 0

(- 1, 3)

Solution steps

x^{2} + y^{2} + 2 x - 6 y - 6 = 0

Rewrite

x^{2} + y^{2} + 2 x - 6 y - 6 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 3)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 1, 3), r = 4

And the center is:

(- 1, 3)

2 x^{2} + 2 y^{2} = 8

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{9}{4}

(x - (- 5))^{2} + (y - 7)^{2} = 11

x^{2} + y^{2} - 6 x - 10 y + 2 = 0

x^{2} + y^{2} - 2 x - 4 y - 4 = 0