What is the center (x+2)^2+y^2=25 ?

The center (x+2)^2+y^2=25 is (-2,0)

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center (x+2)^2+y^2=25

center

(x + 2)^{2} + y^{2} = 25

(- 2, 0)

Solution steps

(x + 2)^{2} + y^{2} = 25

Rewrite

(x + 2)^{2} + y^{2} = 25

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 0)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 2, 0), r = 5

And the center is:

(- 2, 0)

144 x^{2} + 144 y^{2} + 72 x + 192 y + 37 = 0

4 x^{2} + 4 y^{2} + 40 x - 32 y = 5

4 x^{2} + 4 y^{2} + 8 x - y = 0

(x + 2)^{2} + (y + 5)^{2} = 16

x^{2} + (y - 3)^{2} = 16