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Popular >

center x^2+y^2=2

Solution

center

x^{2} + y^{2} = 2

Solution

(0, 0)

Solution steps

x^{2} + y^{2} = 2

Rewrite

x^{2} + y^{2} = 2

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

And the center is:

(0, 0)

Popular Examples

center x^2=16-y^2 center

x^{2} = 16 - y^{2}

center x^2+y^2+10x-4y-7=0 center

x^{2} + y^{2} + 10 x - 4 y - 7 = 0

center x^2+y^2+2x-6y-y=0 center

x^{2} + y^{2} + 2 x - 6 y - y = 0

center (x+6)^2+(y+14)^2=400 center

(x + 6)^{2} + (y + 14)^{2} = 400

center x^2+y^2+x+y=0 center

x^{2} + y^{2} + x + y = 0

Frequently Asked Questions (FAQ)

What is the center x^2+y^2=2 ?
The center x^2+y^2=2 is (0,0)