What is the center x^2+y^2-10x-10y+25=0 ?

The center x^2+y^2-10x-10y+25=0 is (5,5)

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center x^2+y^2-10x-10y+25=0

center

x^{2} + y^{2} - 10 x - 10 y + 25 = 0

(5, 5)

Solution steps

x^{2} + y^{2} - 10 x - 10 y + 25 = 0

Rewrite

x^{2} + y^{2} - 10 x - 10 y + 25 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - 5)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (5, 5), r = 5

And the center is:

(5, 5)

(x - 1)^{2} + y^{2} = 1

x^{2} + y^{2} - 6 x + 2 y + 9 = 0

x^{2} + 2 x + y^{2} - 35 = 0

x^{2} + y^{2} - 6 x = 7

x^{2} + y^{2} + 6 x - 4 y - 12 = 0

What is the center x^2+y^2-10x-10y+25=0 ?
The center x^2+y^2-10x-10y+25=0 is (5,5)