Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

center x^2+y^2-2x+4y-4=0center center x^2+(y-3)^2=25center center 2x^2+2y^2-12x+8y-24=0center center x^2+y^2-6x+8y=144center center x^2+y^2-2x+4y+1=0center

Frequently Asked Questions (FAQ)

  • What is the center x^2+y^2+4x-6y+12=0 ?

    The center x^2+y^2+4x-6y+12=0 is (-2,3)