What is x^2+y^2+16x-4y+58=0 ?

The solution to x^2+y^2+16x-4y+58=0 is Circle with (a,b)=(-8,2),r=sqrt(10)

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x^2+y^2+16x-4y+58=0

x^{2} + y^{2} + 16 x - 4 y + 58 = 0

(a, b) = (- 8, 2), r = 10

Solution steps

x^{2} + y^{2} + 16 x - 4 y + 58 = 0

Rewrite

x^{2} + y^{2} + 16 x - 4 y + 58 = 0

in the form of the standard circle equation

(x - (- 8))^{2} + (y - 2)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (- 8, 2), r = 10

x^{2} + 2 x + y^{2} - 6 y + 6 = 0

x^{2} + y^{2} + 4 x - 6 y - 2 = 0

x^{2} + y^{2} + 8 x - 6 y - 24 = 0

32 = (x - 3)^{2} + (y + 1)^{2}

x^{2} - 10 x + y^{2} + 6 y - 30 = 0

What is x^2+y^2+16x-4y+58=0 ?
The solution to x^2+y^2+16x-4y+58=0 is Circle with (a,b)=(-8,2),r=sqrt(10)