What is x^2-154x+y^2-160y=0 ?

The solution to x^2-154x+y^2-160y=0 is Circle with (a,b)=(77,80),r=sqrt(12329)

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x^2-154x+y^2-160y=0

x^{2} - 154 x + y^{2} - 160 y = 0

(a, b) = (77, 80), r = 12329

Solution steps

x^{2} - 154 x + y^{2} - 160 y = 0

Rewrite

x^{2} - 154 x + y^{2} - 160 y = 0

in the form of the standard circle equation

(x - 77)^{2} + (y - 80)^{2} = (12329)^{2}

Therefore the circle properties are:

(a, b) = (77, 80), r = 12329

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{16} = 10

(x - 4)^{(2)} + (y - 5)^{(2)} = 49

9 - x^{2} > y^{2}

x^{2} + y^{2} - 6 x - 4 y - 18 = 0

x^{2} + y^{2} + 2 x - 12 y + 12 = 0

What is x^2-154x+y^2-160y=0 ?
The solution to x^2-154x+y^2-160y=0 is Circle with (a,b)=(77,80),r=sqrt(12329)