What is 3x^2+3y^2=y+2 ?

The solution to 3x^2+3y^2=y+2 is Circle with (a,b)=(0, 1/6),r= 5/6

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3x^2+3y^2=y+2

3 x^{2} + 3 y^{2} = y + 2

(a, b) = (0, \frac{1}{6}), r = \frac{5}{6}

Solution steps

3 x^{2} + 3 y^{2} = y + 2

Rewrite

3 x^{2} + 3 y^{2} = y + 2

in the form of the standard circle equation

(x - 0)^{2} + (y - \frac{1}{6})^{2} = (\frac{5}{6})^{2}

Therefore the circle properties are:

(a, b) = (0, \frac{1}{6}), r = \frac{5}{6}

x^{2} + (y - 115)^{2} = 11025

y^{2} + x^{2} + 24 x + 10 y + 160 = 0

16 (x^{2} + y^{2}) = 16 (14 x + 6 y + 6)

(x + 4)^{2} + (y - 2)^{2} = \frac{( 8 ^{2} )}{( 5 )}

x^{2} + y^{2} + 5 = 2 x + 8 y + 10

What is 3x^2+3y^2=y+2 ?
The solution to 3x^2+3y^2=y+2 is Circle with (a,b)=(0, 1/6),r= 5/6