What is (x+1)^2+(y-1)^2=61 ?

The solution to (x+1)^2+(y-1)^2=61 is Circle with (a,b)=(-1,1),r=sqrt(61)

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(x+1)^2+(y-1)^2=61

(x + 1)^{2} + (y - 1)^{2} = 61

(a, b) = (- 1, 1), r = 61

Solution steps

(x + 1)^{2} + (y - 1)^{2} = 61

Rewrite

(x + 1)^{2} + (y - 1)^{2} = 61

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = (61)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = 61

x^{2} + y^{2} + 6 x + 22 y + 114 = 0

x^{2} - 10 x + y^{2} - 6 y + 5 = 0

x^{2} + y^{2} - 16 x + 2 y - 20 = 0

(x - 2)^{2} + (y + 3)^{2} = 5^{2}

x^{2} + y^{2} - 6 x - 9 = - 6 y - 1 + 1

What is (x+1)^2+(y-1)^2=61 ?
The solution to (x+1)^2+(y-1)^2=61 is Circle with (a,b)=(-1,1),r=sqrt(61)