What is (x+5)^2+(y+2)^2=21 ?

The solution to (x+5)^2+(y+2)^2=21 is Circle with (a,b)=(-5,-2),r=sqrt(21)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+5)^2+(y+2)^2=21

(x + 5)^{2} + (y + 2)^{2} = 21

(a, b) = (- 5, - 2), r = 21

Solution steps

(x + 5)^{2} + (y + 2)^{2} = 21

Rewrite

(x + 5)^{2} + (y + 2)^{2} = 21

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 2))^{2} = (21)^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 2), r = 21

0 = 3 - 6 (x^{2} + y^{2})

x^{2} + y^{2} + (- x^{2} + y^{2})^{2} = 9

(x - 3)^{2} + (y + 5)^{2} = 100

π x^{(2)} + π y^{(2)} + 8 x - 10 π y - 400 = 0

x^{2} + y^{2} + 14 x + 8 y + 3 = 0

What is (x+5)^2+(y+2)^2=21 ?
The solution to (x+5)^2+(y+2)^2=21 is Circle with (a,b)=(-5,-2),r=sqrt(21)