What is 2x^2+8x+2y^2-18y=-33/2 ?

The solution to 2x^2+8x+2y^2-18y=-33/2 is Circle with (a,b)=(-2, 9/2),r=4

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2x^2+8x+2y^2-18y=-33/2

2 x^{2} + 8 x + 2 y^{2} - 18 y = - \frac{33}{2}

(a, b) = (- 2, \frac{9}{2}), r = 4

Solution steps

2 x^{2} + 8 x + 2 y^{2} - 18 y = - \frac{33}{2}

Rewrite

2 x^{2} + 8 x + 2 y^{2} - 18 y = - \frac{33}{2}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - \frac{9}{2})^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 2, \frac{9}{2}), r = 4

x^{2} + 4 x + y^{2} - 14 y = - 3

(x - 1)^{2} + (y + 2)^{2} + (x - 4)^{2} + (y - 6)^{2} = 73

x^{2} + y^{2} + 28 x - 32 y + 448 = 0

3 x^{2} + 3 y^{2} = 243

x^{2} + 6 x + y^{2} = 16 y - 68

What is 2x^2+8x+2y^2-18y=-33/2 ?
The solution to 2x^2+8x+2y^2-18y=-33/2 is Circle with (a,b)=(-2, 9/2),r=4